在
Python,PHP和许多其他语言中,可以转换html文档并“美化”它.在Go中,使用MarshIndent函数可以非常轻松地完成JSON和XML(来自结构/接口).
Go中的XML示例：
http://play.golang.org/p/aBNfNxTEG1
package main
import (
"encoding/xml"
"fmt"
"os"
)
func main() {
type Address struct {
City,State string
}
type Person struct {
XMLName xml.Name `xml:"person"`
Id int `xml:"id,attr"`
FirstName string `xml:"name>first"`
LastName string `xml:"name>last"`
Age int `xml:"age"`
Height float32 `xml:"height,omitempty"`
Married bool
Address
Comment string `xml:",comment"`
}
v := &Person{Id: 13,FirstName: "John",LastName: "Doe",Age: 42}
v.Comment = " Need more details. "
v.Address = Address{"Hanga Roa","Easter Island"}
output,err := xml.MarshalIndent(v," "," ")
if err != nil {
fmt.Printf("error: %v\n",err)
}
os.Stdout.Write(output)
}
但是,这仅适用于将struct / interface转换为[]字节.我想要的是自动转换一串HTML代码和缩进.例：
原始HTML
<!doctype html><html><head> <title>Website Title</title> </head><body> <div class="random-class"> <h1>I like pie</h1><p>It's true!</p></div> </body></html>
Prettified HTML
<!doctype html>
<html>
<head>
<title>Website Title</title>
</head>
<body>
<div class="random-class">
<h1>I like pie</h1>
<p>It's true!</p>
</div>
</body>
</html>
如何使用字符串完成这项工作？
