Web服务 – Spring Web-Service解组无法正常工作

前端之家收集整理的这篇文章主要介绍了Web服务 – Spring Web-Service解组无法正常工作前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。
我已经像这样配置了我的WebService:

的applicationContext:

<sws:annotation-driven />    
 <bean class="org.springframework.ws.server.endpoint.mapping.PayloadRootAnnotationMethodEndpointMapping" >
<property name="interceptors">
 <list>
    <bean class="org.springframework.ws.server.endpoint.interceptor.PayloadLoggingInterceptor"/>
</list>
</property>

注意:Interceptor在启动时加载,但如果有请求,则不会写任何内容.

我有一个PersonServiceImpl类,方法是addPersonRequest().如果我使用org.dom4j.Element作为方法参数,一切正常;

@Endpoint
public class PersonServiceImpl {
     @PayloadRoot(namespace = "http://www.example.org/person/schema",localPart = "AddPersonRequest")
     @ResponsePayload
       public AddPersonRequest addPersonRequest(@RequestPayload Element element) {
        System.out.println(element.asXML());
        Person response = new Person();
        response.setId(2);
        response.setFirstName("Mad");
        response.setLastName("Mike");
        return response;
     }
}

但是,如果我改变我的方法参数,如下所示(因此应该使用spring-ws的自动编组),request.getFirstName()打印为null. (JAXB2在类路径上).

Person-class使用@XMLType和@XMLRootElement进行注释.

注意:编组工作正常.

@Endpoint
public class PersonServiceImpl {
     @PayloadRoot(namespace = "http://www.example.org/person/schema",localPart = "AddPersonRequest")
     @ResponsePayload
       public AddPersonRequest addPersonRequest(@RequestPayload Person request,SoapHeader header) {
        System.out.println(header.getName());
        System.out.println(request.getFirstName());
        Person response = new Person();
        response.setId(2);
        response.setFirstName("Mad");
        response.setLastName("Mike");
        return response;
     }
}

Person.java:

@XmlType
@XmlRootElement(namespace="http://www.example.org/person/schema",name="Person")
public class Person implements Serializable {

    private int id;
    private String firstName;
    private String lastName;

    @XmlElement
    public String getFirstName() {
        return firstName;
    }
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    @XmlElement
    public String getLastName() {
        return lastName;
    }
    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    @XmlAttribute
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
}

通过soapUI发送的测试请求(从wsdl生成):

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sch="http://www.example.org/person/schema"> 
<soapenv:Header/>
<soapenv:Body>

  <sch:AddPersonRequest>

     <sch:Person sch:Id="1">

        <sch:FirstName>firstname</sch:FirstName>

        <sch:LastName>lastname</sch:LastName>

     </sch:Person>

  </sch:AddPersonRequest>

</soapenv:Body>
</soapenv:Envelope>

解决方法

你提到编组正在工作我没有看到为什么解组不起作用的原因,你是否测试了马歇尔和解散在isloation?

只是为了确保soap请求是好的,你可以添加日志拦截器并打印来自客户端访问Web服务的实际请求,将此片段添加到您的上下文文件

<sws:interceptors>
    <bean class="org.springframework.ws.soap.server.endpoint.interceptor.SoapEnvelopeLoggingInterceptor">
        <property name="logRequest" value="true"></property>
        <property name="logResponse" value="true"></property>
    </bean>
</sws:interceptors>

您应该看到这样的日志消息包含整个soap请求,我正在从saop UI添加日志消息请求

DEBUG [http-8080-2]:endpoint.interceptor.SoapEnvelopeLoggingInterceptor.logMessage - Request:
    <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:sch="http://hoost:port/context/patient/schemas">
      <soapenv:Header/>
         <soapenv:Body>
            <sch:addRequest>
              <sch:patient>
                  <sch:id>?</sch:id>
                     <sch:lastname>Joe</sch:lastname>
                </sch:patient>
             </sch:addRequest>
        </soapenv:Body>
      </soapenv:Envelope>

更新的答案

这可能是你的肥皂要求不确定

<sch:FirstName>firstname</sch:FirstName> (this should be)

        <sch:firstName>firstname</sch:firstName>

另一个更新

例外是由于您定义终点的方式,在您的soap请求(sch:AddPersonRequest)中,您发送的是addPersonRequest而不是Person作为有效负载,因此更改终点以反映出来,@ RequestPayload应该是AddPersonRequest而不是Person

@PayloadRoot(namespace = "http://www.example.org/person/schema",localPart = "AddPersonRequest")
     @ResponsePayload
      public AddPersonRequest addPersonRequest(@RequestPayload AddPersonRequest request,SoapHeader header) {
原文链接:https://www.f2er.com/html/225679.html

猜你在找的HTML相关文章