我试图在我的页面上的两个点之间划一条线.图像可以拖动并放置在DIV中,因此它们的位置可以改变,但线仍然需要连接它们.
到目前为止,我只尝试了一个自定义行来启动它.
var s = document.getElementById("Red1X");
var x = 200,y = 200;
s.style.x2 = x + "px";
s.style.y2 = y + "px";
function allowDrop(ev) {
ev.preventDefault();
}
function drag(ev) {
ev.dataTransfer.setData("text",ev.target.id);
}
function drop(ev) {
ev.preventDefault();
var data = ev.dataTransfer.getData("text");
ev.target.appendChild(document.getElementById(data));
}
#div1 {
width: 17px;
height: 17px;
padding: 0px;
border: 1px solid #aaaaff;
float: left
}
<div id="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div id="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div id="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <img id="RED1" src="http://i.imgur.com/By4xvE5.png" draggable="true" ondragstart="drag(event)" align="left"> <img id="RED2" src="http://i.imgur.com/By4xvE5.png" draggable="true" ondragstart="drag(event)" align="left"> <svg height="500" width="500"> <line id="Red1X" x1="0" y1="0" x2="100" y2="200" style="stroke:rgb(255,0);stroke-width:3" /> </svg>
解决方法
好的,正如评论中所提到的,当点在同一条线上时相对容易.
如果你有一个在另一个之上变得更复杂 – 那么你基本上需要：角度,将它应用于CSS变换：旋转属性,以及两个点/元素之间的长度,以重新计算宽度,因为它不再是直线.我讨厌数学:),所以我使用来自互联网的好人的知识：http://jsfiddle.net/codepo8/bAwUf/light/(信用到codepo8)
两条最重要的路线：
var angle= Math.atan2(red2.offsetTop - red1.offsetTop,red2.offsetLeft - red1.offsetLeft) * 180 / Math.PI; var length = Math.sqrt((red2.offsetLeft-red1.offsetLeft) * (red2.offsetLeft-red1.offsetLeft) + (red2.offsetTop-red1.offsetTop) * (red2.offsetTop-red1.offsetTop));
现在,您的脚本应该是这样的：
var s = document.querySelector(".line");
red1=document.getElementById('RED1');
red2=document.getElementById('RED2');
function allowDrop(ev) {
ev.preventDefault();
}
function drag(ev) {
ev.dataTransfer.setData("text",ev.target.id);
}
function drop(ev) {
ev.preventDefault();
var data = ev.dataTransfer.getData("text");
ev.target.appendChild(document.getElementById(data));
s.style.left=red1.offsetLeft+5+'px';
s.style.top=red1.offsetTop+5+'px';
s.style.visibility='visible';
var angle= Math.atan2(red2.offsetTop - red1.offsetTop,red2.offsetLeft - red1.offsetLeft) * 180 / Math.PI;
var length = Math.sqrt((red2.offsetLeft-red1.offsetLeft) * (red2.offsetLeft-red1.offsetLeft) + (red2.offsetTop-red1.offsetTop) * (red2.offsetTop-red1.offsetTop));
s.style.width=Math.abs(length)+'px';
s.style.transform="rotate("+Math.round(angle)+"deg)";
s.style.transformOrigin ="0 0";
}
.div1 {
width: 150px;
height: 150px;
padding: 0px;
border: 1px solid #aaaaff;
float: left;
}
.line {
position:absolute;
height:3px;
background:red;
width:100px;
z-index:999;
visibility:hidden;
}
<div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <div class="div1" ondrop="drop(event)" ondragover="allowDrop(event)"></div> <img id="RED1" src="http://i.imgur.com/By4xvE5.png" draggable="true" ondragstart="drag(event)" align="left"> <img id="RED2" src="http://i.imgur.com/By4xvE5.png" draggable="true" ondragstart="drag(event)" align="left"> <div class="line"> </div>
这是一个很好的起点,我猜(很少有东西可以让它完美),但我想你会得到它……
演示(更好地在这里看到它,片段不是很好,对于这种演示)：https://jsfiddle.net/dxre19o6/
