1.普通视图获取对应位置图素@H_404_1@

CCTMXLayer *layer=map->layerNamed("Layer 0");@H_404_1@

CCSize s=layer->getLayerSize();@H_404_1@

@H_404_1@

CCPoint touchPoint=touch->getLocationInView();@H_404_1@

@H_404_1@

touchPoint=CCDirector::sharedDirector()->convertToGL(touchPoint);@H_404_1@

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int indexx=(touchPoint.x)/map->getTileSize().width;@H_404_1@

int indexy=map->getMapSize().height-(touchPoint.y)/map->getTileSize().height;@H_404_1@

sprite=layer->tileAt(ccp(indexx,indexy));@H_404_1@

sprite->setScale(2);@H_404_1@

@H_404_1@

//map->getMapSize().height 获取图片的长宽像素个数@H_404_1@

//getTileSize().height 获取一个图素的高度与宽度@H_404_1@

总体思路就是具体位置除以图素的宽高，但这里需要注意，在Y轴的处理上略有不同。因为Cocos2D-X中的坐标系中，Y轴是从下到上一次增加的，而地图中的行数则是从上到下增加的，这就需要做一个转换，用总的函数减去Y轴坐标除以图素高，结果才是所有图素的函数。@H_404_1@

@H_404_1@

2.45度角视图获取对应图素@H_404_1@

CCPoint HelloWorld::converttto2d(float x,float y)@H_404_1@

{@H_404_1@

CCTMXTiledMap *map=(CCTMXTiledMap *)getChildByTag(1);@H_404_1@

int mapWidth=map->getMapSize().width*map->getTileSize().width;@H_404_1@

int mapHeight=map->getMapSize().height*map->getTileSize().height;@H_404_1@

@H_404_1@

double distanse,sin1,sin11,sin22,cos11,cos1;@H_404_1@

int d2x,d2y;@H_404_1@

double mystatic5=sqrt(5.0);@H_404_1@

double mystatic=16*mystatic5;@H_404_1@

if (x>mapWidth/2)@H_404_1@

{@H_404_1@

distanse=sqrt((x-mapWidth/2)*(x-mapWidth/2)+(mapHeight-y)*(mapHeight-y));@H_404_1@

sin1=(mapHeight-y)/distanse;@H_404_1@

cos1=(x-mapWidth/2)/distanse;@H_404_1@

sin11=(sin1*2-cos1)/mystatic5;@H_404_1@

cos11=(sin1+cos1*2)/mystatic5;@H_404_1@

d2y=distanse*5/4*sin11/mystatic;@H_404_1@

sin22=(2*sin1+cos1)/mystatic5;@H_404_1@

d2x=distanse*5/4*sin22/mystatic;@H_404_1@

return ccp(d2x.d2y);@H_404_1@

}@H_404_1@

else@H_404_1@

{@H_404_1@

distanse=sqrt((mapWidth/2-x)*(mapWidth/2-x)+(mapHeight-y)*(mapHeight-y));@H_404_1@

sin1=(mapHeight-y)/distanse;@H_404_1@

cos1=(mapWidth/2-x)/distanse;@H_404_1@

sin11=(sin1*2-cos1)/mystatic5;@H_404_1@

cos11=(sin1+cos1*2)/mystatic5;@H_404_1@

d2x=distanse*5/4*sin11/mystatic;@H_404_1@

sin22=(2*sin1+cos1)/mystatic5;@H_404_1@

d2y=distanse*5/4*sin22/mystatic;@H_404_1@

return ccp(d2x,d2y);@H_404_1@

}@H_404_1@

}@H_404_1@