它包含在Leopard& amp;后来.

>>> from Foundation import *
>>> a = NSArray.arrayWithObjects_("a","b","c",None)
>>> a
(
      a,b,c
)
>>> a[1]
'b'
>>> a.objectAtIndex_(1)
'b'
>>> type(a)
<objective-c class NSCFArray at 0x7fff708bc178>

它甚至适用于iPython：

In [1]: from Foundation import *

In [2]: a = NSBundle.allFrameworks()

In [3]: ?a
Type:       NSCFArray
Base Class: <objective-c class NSCFArray at 0x1002adf40>

`

要从Objective-C调用Python,最简单的方法是：

>在Objective-C中声明一个包含要调用的API的抽象超类
>在类的@implementation中创建方法的存根实现
>在Python中对类进行子类化并提供具体实现
>在抽象超类上创建一个工厂方法,创建具体的子类实例

即

@interface Abstract : NSObject
- (unsigned int) foo: (NSString *) aBar;
+ newConcrete;
@end

@implementation Abstract
- (unsigned int) foo: (NSString *) aBar { return 42; }
+ newConcrete { return [[NSClassFromString(@"MyConcrete") new] autorelease]; }
@end

.....

class Concrete(Abstract):
    def foo_(self,s): return s.length()

.....

x = [Abstract newFoo];
[x  foo: @"bar"];