我想从TinyXml输出中解析一组元素.本质上,我需要选择端口元素的“portid”属性,该端口的状态为“open”(如下面的端口23所示).
<?xml version="1.0" ?>
<nmaprun>
<host>
<ports>
<port protocol="tcp" portid="22">
<state state="filtered"/>
</port>
<port protocol="tcp" portid="23">
<state state="open "/>
</port>
<port protocol="tcp" portid="24">
<state state="filtered" />
</port>
<port protocol="tcp" portid="25">
<state state="filtered" />
</port>
<port protocol="tcp" portid="80">
<state state="filtered" />
</port>
</ports>
</host>
</nmaprun>
解决方法
这将大致如下：
TiXmlHandle docHandle( &doc );
TiXmlElement* child = docHandle.FirstChild( "nmaprun" ).FirstChild( "host" ).FirstChild( "ports" ).FirstChild( "port" ).ToElement();
int port;
string state;
for( child; child; child=child->NextSiblingElement() )
{
port = atoi(child->Attribute( "portid"));
TiXmlElement* state_el = child->FirstChild()->ToElement();
state = state_el->Attribute( "state" );
if ("filtered" == state)
cout << "port: " << port << " is filtered! " << endl;
else
cout << "port: " << port << " is unfiltered! " << endl;
}
