在像GDB或Valgrind这样的几个调试包中,可以请求不对C类型进行解码.有没有类似的方法强制G只输出损坏的类型名称,削减所有不必要的输出？

澄清

由于给出了第一个答案,我发现问题不明确.考虑以下MWE：

template <typename T>
class A
{
    public:
        T foo;
};

template <typename T>
class B
{       
};

template <typename T>
class C
{
    public:
        void f(void)
        {
            this->foo = T(1);

            this->bar = T(2);
        }
};

typedef C< B< B< B< B< A<int> > > > > > myType;

int main(int argc,char** argv)
{
    myType err;

    err.f();

    return 0;
};

行中的错误 – > bar = T(2);仅当类型为C< myType>的对象时才会出错实例化并调用方法C :: f().因此,G沿这些行返回错误消息：

test.cpp: In instantiation of ‘void C<T>::f() [with T = B<B<B<B<A<int> > > > >]’:
test.cpp:33:8:   required from here
test.cpp:21:14: error: no matching function for call to ‘B<B<B<B<A<int> > > > >::B(int)’
    this->foo = T(1);
              ^
test.cpp:21:14: note: candidates are:
test.cpp:11:7: note: B<B<B<B<A<int> > > > >::B()
 class B
       ^
test.cpp:11:7: note:   candidate expects 0 arguments,1 provided
test.cpp:11:7: note: B<B<B<B<A<int> > > > >::B(const B<B<B<B<A<int> > > > >&)
test.cpp:11:7: note:   no known conversion for argument 1 from ‘int’ to ‘const B<B<B<B<A<int> > > > >&’
test.cpp:21:14: error: ‘class C<B<B<B<B<A<int> > > > > >’ has no member named ‘foo’
    this->foo = T(1);
              ^
test.cpp:23:14: error: no matching function for call to ‘B<B<B<B<A<int> > > > >::B(int)’
    this->bar = T(2);
              ^
test.cpp:23:14: note: candidates are:
test.cpp:11:7: note: B<B<B<B<A<int> > > > >::B()
 class B
       ^
test.cpp:11:7: note:   candidate expects 0 arguments,1 provided
test.cpp:11:7: note: B<B<B<B<A<int> > > > >::B(const B<B<B<B<A<int> > > > >&)
test.cpp:11:7: note:   no known conversion for argument 1 from ‘int’ to ‘const B<B<B<B<A<int> > > > >&’
test.cpp:23:14: error: ‘class C<B<B<B<B<A<int> > > > > >’ has no member named ‘bar’
    this->bar = T(2);

类型名称在这里很烦人,但是当完整的类型名称需要数百个字符时,无法读取.有没有办法向GCC询问损坏的类型名称而不是全名,或以某种方式限制其长度？

STLFilt

不幸的是,STLFilt只使输出更漂亮;长度不变.事实上,输出被分成多行的事实使整个事情变得更糟,因为输出占用更多空间.