我的问题与这个
OpenGl goes too dark完全相同,但答案对我不起作用.我试图通过转换为纹理的表面来显示图像,结果太黑了：
原版的：
在openGL之后
左边是原版,右边是OpenGl img.
这是我的代码：
void TexturedRect::draw(int scroll){
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glBindTexture(GL_TEXTURE_2D,_texture);
glEnable(GL_TEXTURE_2D);
glBegin(GL_QUADS); //Begining the cube's drawing
int x = this->getX();
int y = this->getY();
int w = this->getWidth();
int h = this->getHeight();
int z = this->getZ();
/*
(0,0) ------ (1,0)
| |
| |
(0,1) ------ (1,1)
*/
glTexCoord3i(0,1);glVertex3i(x + scroll,y,z);
glTexCoord3i(_tv,1);glVertex3i(x + w * _tv + scroll,_tu,y + h * _tu,z);
glTexCoord3i(0,z);
glEnd();
glDisable(GL_TEXTURE_2D);
}
void TexturedRect::createTextureFromSurface()
{
SDL_Surface * surface = IMG_Load(filename.toStdString().c_str());
// get the number of channels in the SDL surface
GLint nbOfColors = surface->format->BytesPerPixel;
GLenum textureFormat = 0;
switch (nbOfColors) {
case 1:
textureFormat = GL_ALPHA;
break;
case 3: // no alpha channel
if (surface->format->Rmask == 0x000000ff)
textureFormat = GL_RGB;
else
textureFormat = GL_BGR;
break;
case 4: // contains an alpha channel
if (surface->format->Rmask == 0x000000ff)
textureFormat = GL_RGBA;
else
textureFormat = GL_BGRA;
break;
default:
qDebug() << "Warning: the image is not truecolor...";
break;
}
glEnable( GL_TEXTURE_2D );
// Have OpenGL generate a texture object handle for us
glGenTextures( 1,&_texture );
// Bind the texture object
glBindTexture( GL_TEXTURE_2D,_texture );
// Edit the texture object's image data using the information SDL_Surface gives us
glTexImage2D( GL_TEXTURE_2D,nbOfColors,surface->w,surface->h,textureFormat,GL_UNSIGNED_BYTE,surface->pixels );
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MIN_FILTER,GL_NEAREST);
glTexParameteri(GL_TEXTURE_2D,GL_TEXTURE_MAG_FILTER,GL_NEAREST);
}
解决方法
您可能在代码中的其他位置设置了一些状态,当您希望禁用它来绘制此四边形时,该状态仍然处于启用状态.
尝试在glBindTexture(GL_TEXTURE_2D,_texture)之后添加以下内容;在你的绘图代码中(重要的是它在draw方法中完成而不是createTextureFromSurface方法)：
glDisable(GL_BLEND); glDisable(GL_LIGHTING); glTexEnvi( GL_TEXTURE_ENV,GL_TEXTURE_ENV_MODE,GL_REPLACE ) glColor3f(1.0f,1.0f,1.0f);
如果这样可行,您可以逐个注释掉它们,以确定导致问题的状态.绘制此四边形时禁用的任何状态都需要在绘制需要它的对象时重新启用.
