题
如何从C中的路径名中提取基本路径？
C语言或C运行时库中是否有任何函数可以从C中的路径名中提取基本路径？
我问基本上与this问题相反.
注意：我更喜欢跨平台解决方案,但我在Windows中工作,所以如果有一个Windows API调用这样做,我仍然想知道.
例子
Input | Output --------------------------------- C:\path\to\file -> C:\path\to\ C:\path\to\file.c -> C:\path\to\ C:\file -> C:\ .\file -> .\ .\ -> .\ \ -> \
参考
解决方法
在Windows上有
_splitpath.
例
#include <Windows.h>
#include <tchar.h>
// Use your own error codes here
#define SUCCESS 0L
#define FAILURE_NULL_ARGUMENT 1L
#define FAILURE_API_CALL 2L
#define FAILURE_INSUFFICIENT_BUFFER 3L
DWORD GetBasePathFromPathName( LPCTSTR szPathName,LPTSTR szBasePath,DWORD dwBasePathSize )
{
TCHAR szDrive[_MAX_DRIVE] = { 0 };
TCHAR szDir[_MAX_DIR] = { 0 };
TCHAR szFname[_MAX_FNAME] = { 0 };
TCHAR szExt[_MAX_EXT] = { 0 };
size_t PathLength;
DWORD dwReturnCode;
// Parameter validation
if( szPathName == NULL || szBasePath == NULL )
{
return FAILURE_NULL_ARGUMENT;
}
// Split the path into it's components
dwReturnCode = _tsplitpath_s( szPathName,szDrive,_MAX_DRIVE,szDir,_MAX_DIR,szFname,_MAX_FNAME,szExt,_MAX_EXT );
if( dwReturnCode != 0 )
{
_ftprintf( stderr,TEXT("Error splitting path. _tsplitpath_s returned %d.\n"),dwReturnCode );
return FAILURE_API_CALL;
}
// Check that the provided buffer is large enough to store the results and a terminal null character
PathLength = _tcslen( szDrive ) + _tcslen( szDir );
if( ( PathLength + sizeof( TCHAR ) ) > dwBasePathSize )
{
_ftprintf( stderr,TEXT("Insufficient buffer. required %d. Provided: %d\n"),PathLength,dwBasePathSize );
return FAILURE_INSUFFICIENT_BUFFER;
}
// Copy the szDrive and szDir into the provide buffer to form the basepath
if( ( dwReturnCode = _tcscpy_s( szBasePath,dwBasePathSize,szDrive ) ) != 0 )
{
_ftprintf( stderr,TEXT("Error copying string. _tcscpy_s returned %d\n"),dwReturnCode );
return FAILURE_API_CALL;
}
if( ( dwReturnCode = _tcscat_s( szBasePath,szDir ) ) != 0 )
{
_ftprintf( stderr,TEXT("Error copying string. _tcscat_s returned %d\n"),dwReturnCode );
return FAILURE_API_CALL;
}
return SUCCESS;
}
