参见英文答案 >
Scanf skips every other while loop in C10个
#include "stdio.h" int main(void) { int order,nextp,N=3; char cont; nextp = 0; printf("\nShould we continue (y or n): "); scanf("%c",&cont); if (cont != 'y') return; for(; nextp < N; nextp++) { printf("Enter order number: "); scanf("%d",&order); printf("you have entered %d\n",order); printf("okay now continue with cont\n"); printf("enter cont y or n: "); scanf("%c",&cont); if (cont != 'y') { printf("\nnot equal to y\n"); break; } printf("after intepreting t[0]"); } return 0; }
输出看起来像这样
Should we continue (y or n): y Enter order number: 45 you have entered 45 okay now continue with cont enter cont y or n: not equal to y
第二个输入被跳过了.为什么?
解决方法
由于stdin中已经存在换行符,这种情况正在发生.
使用
使用
scanf(" %c",&cont);
代替
scanf("%c",&cont);
注意%c之前的一个空格.