我正在尝试转换一个向量< int>到矢量< string>.使用std :: transform我使用std :: to_string将int转换为字符串,但我不断收到错误.这是我的代码
- #include <vector>
- #include <iostream>
- #include <algorithm>
- #include <string>
- int main(){
- std::vector<int> v_int;
- std::vector<std::string> v_str;
- for(int i = 0;i<5;++i)
- v_int.push_back(i);
- v_str.resize(v_int.size());
- std::transform(v_int.begin(),v_int.end(),v_str.begin(),std::to_string);
- }
但我收到这个错误
- no matching function for call to 'transform'
- std::transform(v_int.begin(),std::to_string);
- ^~~~~~~~~~~~~~
- /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/algorithm:1951:1: note:
- candidate template ignored: couldn't infer template argument
- '_UnaryOperation'
- transform(_InputIterator __first,_InputIterator __last,_OutputIterato...
- ^
- /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/algorithm:1961:1: note:
- candidate function template not viable: requires 5 arguments,but 4 were
- provided
- transform(_InputIterator1 __first1,_InputIterator1 __last1,_InputItera...
解决方法
std::to_string是一个超载的功能,所以你需要提供一个演员来消除歧义
- std::transform(v_int.begin(),static_cast<std::string(*)(int)>(std::to_string));
或使用lambda
- std::transform(v_int.begin(),[](int i){ return std::to_string(i); });
