以下是NSTimer中的Objective-C类别,以进行基于块的NSTimers的触发.我看不到任何错误,但是我得到的是,我传递给schedule …方法的块正在被释放,尽管我打电话给它.
我失踪了什么
typedef void(^NSTimerFiredBlock)(NSTimer *timer);
@implementation NSTimer (MyExtension)
+ (void)timerFired:(NSTimer *)timer
{
NSTimerFiredBlock blk = timer.userInfo;
if (blk != nil) {
blk(timer);
}
}
+ (NSTimer *)scheduledTimerWithTimeInterval:(NSTimeInterval)seconds
repeats:(BOOL)repeats
callback:(NSTimerFiredBlock)blk
{
return [NSTimer scheduledTimerWithTimeInterval:seconds
target:self
selector:@selector(timerFired:)
userInfo:[blk copy]
repeats:repeats];
}
@end
解决方法
我发现这个代码在http://orion98mc.blogspot.ca/2012/08/objective-c-blocks-for-fun.html
做得好
NSTimer *timer = [NSTimer scheduledTimerWithTimeInterval:0.7
target:[NSBlockOperation blockOperationWithBlock:^{ /* do this! */ }]
selector:@selector(main)
userInfo:nil
repeats:NO
];
