我有很多麻烦,试图从C库中找出排序函数,并尝试从a-z中排序字符串数组,请帮助！
我被告知使用这个,但我不知道我做错了什么.
// std::sort(stringarray.begin(),stringarray.end());
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main()
{
int z = 0;
string name[] = {"john","bobby","dear","test1","catherine","nomi","shinta","martin","abe","may","zeno","zack","angeal","gabby"};
sort(name[0],name[z]);
for(int y = 0; y < z; y++)
{
cout << name[z] << endl;
}
return 0;
}
解决方法
int z = sizeof(name)/sizeof(name[0]); //Get the array size
sort(name,name+z); //Use the start and end like this
for(int y = 0; y < z; y++){
cout << name[y] << endl;
}
编辑：
考虑到所有“适当的”命名约定(根据注释)：
int N = sizeof(name)/sizeof(name[0]); //Get the array size
sort(name,name+N); //Use the start and end like this
for(int i = 0; i < N; i++){
cout << name[i] << endl;
}
注意：DietmarKühl的答案在各方面都是最好的,std :: begin()& std :: end()应该用于std :: sort与C 11的函数,否则可以定义它们.
