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How do I initialize a member array with an initializer_list?5个
这是否可能？
这是否可能？
#include <array>
#include <initializer_list>
struct A
{
A ( std::initializer_list< int > l )
: m_a ( l )
{
}
std::array<int,2> m_a;
};
int main()
{
A a{ 1,2 };
}
但是这会导致这个错误：
t.cpp: In constructor ‘A::A(std::initializer_list<int>)’:
t.cpp:7:19: error: no matching function for call to ‘std::array<int,2ul>::array(std::initializer_list<int>&)’
: m_a ( l )
^
t.cpp:7:19: note: candidates are:
In file included from t.cpp:1:0:
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: std::array<int,2ul>::array()
struct array
^
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: candidate expects 0 arguments,1 provided
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int,2ul>::array(const std::array<int,2ul>&)
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘const std::array<int,2ul>&’
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int,2ul>::array(std::array<int,2ul>&&)
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘std::array<int,2ul>&&’
