我正在看下面的程序,不知道如何分配内存,为什么：
void function() {
char text1[] = "SomeText";
char* text2 = "Some Text";
char *text = (char*) malloc(strlen("Some Text") + 1 );
}
在上面的代码中,最后一个代码显然是在堆中.但是,据了解,text2在程序的数据段中,而text1可能位于堆栈中.还是我的假设错了？这里有什么正确的假设？这个编译器是否依赖？
谢谢
解决方法
// Array allocated on the stack and initialized with "SomeText" string.
// It has automatic storage duration. You shouldn't care about freeing memory.
char text1[] = "SomeText";
// Pointer to the constant string "Some Text".
// It has static storage duration. You shouldn't care about freeing memory.
// Note that it should be "a pointer to const".
// In this case you'll be protected from accidential changing of
// the constant data (changing constant object leads to UB).
const char* text2 = "Some Text";
// malloc will allocate memory on the heap.
// It has dynamic storage duration.
// You should call "free" in the end to avoid memory leak.
char *text = (char*) malloc(strlen("Some Text") + 1 );
