如果我有一个看起来像这样的方法：
- (NSDictionary *)removeDataInDictionary:(NSDictionary *)dictionary {
NSMutableDictionary *mutableDictionary = [dictionary mutableCopy];
[mutableDictionary removeObjectForKey:@"key"];
// Return option 1
return [NSDictionary dictionaryWithDictionary:mutableDictionary];
// Return option 2
return (NSDictionary *) mutableDictionary;
}
是选项1“更好”的代码,因为它将真的返回一个NSDictionary,而选项2将实际返回一个NSMutableDictionary伪装成一个NSDictionary？
