这是我的C程序
- #include <stdio.h>
- struct xyx {
- int x;
- int y;
- char c;
- char str[20];
- int arr[2];
- };
- int main(void)
- {
- struct xyz a;
- a.x = 100;
- printf("%d\n",a.x);
- return 0;
- }
这是我得到的错误….
按ENTER或键入命令继续
- 13structtest.c: In function ‘main’:
- 13structtest.c:13:13: error: storage size of ‘a’ isn’t known
- 13structtest.c:13:13: warning: unused variable ‘a’ [-Wunused-variable]
解决方法
你的结构称为struct xyx,但是一个是struct xyz.
Once you fix that,the output is
100.
- #include <stdio.h>
- struct xyx {
- int x;
- int y;
- char c;
- char str[20];
- int arr[2];
- };
- int main(void)
- {
- struct xyx a;
- a.x = 100;
- printf("%d\n",a.x);
- return 0;
- }
