message ParamsMessage {
required int32 temperature = 1;
}
message MasterMessage {
enum Type { GETPARAMS = 1; SENDPARAMS = 2;}
required Type type = 1;
optional ParamsMessage paramsMessage = 2;
}
我现在以下列方式创建MasterMessage：
ParamsMessage * params = new ParamsMessage(); params->set_temperature(22); MasterMessage master; master.set_type(MasterMessage::SENDPARAMS); master.set_allocated_paramsmessage(params);
问题是：在处理消息后,我有没有删除params消息,或者将原型交易给我？我在文档中找不到任何东西.
解决方法
从这里：https://developers.google.com/protocol-buffers/docs/reference/cpp-generated
void set_allocated_foo(string* value): Sets the string object to the@H_502_18@ field and frees the prevIoUs field value if it exists. If the string@H_502_18@ pointer is not NULL,the message takes ownership of the allocated@H_502_18@ string object and has_foo() will return true. Otherwise,if the value@H_502_18@ is NULL,the behavior is the same as calling clear_foo(). string*
release_foo(): Releases the ownership of the field and returns the@H_502_18@ pointer of the string object. After calling this,caller takes the@H_502_18@ ownership of the allocated string object,has_foo() will return false,@H_502_18@ and foo() will return the default value.
这意味着：只要你不调用release_ *,protobuf将会处理删除对象.如果在处理Protobuf消息后需要对象,则需要使用release_ *进行相关处理,这将阻止Protobuf删除对象.
