翻译句子中的单词

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我现在要经过K.N. King’s C编程:一种现代方法.我已经超过了第8章(阵列)的文本,我很想转到第9章,但我还没有在每一章的最后解决所谓的“编程项目”.不幸的是,第14个…让我烦恼.

Write a program that reverses the words in a sentence.

Enter a sentence: you can cage a swallow can't you?
Reversal of sentence: you can't swallow a cage can you?

Hint: Use a loop to read the characters one by one and store them in a one-dimensional char array. Have the loop stop at a period,question mark,or exclamation point (the “terminating character “),which is saved in a separate char variable. Then use a second loop to search backward through the array for the beginning of the last word. Print the last word,then search backward for the next-to-last word. Repeat until the beginning of the array is reached. Finally,print the terminating character.

我一直在考虑将一个单词定义为空格之间的一系列字符.因此,当到达空间时,向后移动,打印每个字符,直到找到另一个空格.我的第一个版本的程序只打印了第一个单词.它的当前版本只打印其他单词.我已经坚持了两天,所以任何帮助都真的很感激.这是我的代码,以及输出示例.希望我已正确记录我的代码.提前致谢!

/* Include the standard I/O library */
#include<stdio.h>

/* Define main */
int main(void) {

    /**
     * Declare an array of characters storing the sentence,as well as
     * a character representing the current character under cursor and
     * the terminating character
     */
    char sentence[100] = { ' ' },c,tc;

    /**
     * Declare a loop counter already initialized at 0,an incremental
     * variable,as well as the size of the read sentence
     */
    int i = 0,j = 1,size = 0;

    /* Get the sentence */
    printf("Enter a sentence: \n");
    for(c = getchar(); (c != '.') && (c != '!') && 
        (c != '?') && (c != '\n'); c = getchar(),i++) {

        sentence[i] = c; /* Store the current character in the array */
        size++; /* Increase the sentence's size */
    }

    tc = c; /* Get the terminating character */

    /**
     * Go backward through the array,printing each sequence of characters
     * between spaces
     */
    for(i = 99; i >= 0; i--) {

        if(sentence[i] == ' ') {

            while(sentence[i + j] != ' ') {

                printf("%c",sentence[i + j]);
                j++;
            }

            j = 1; /* Reset the incremental variable */
            printf(" "); /* Print a tailing space */
        }
    }

    /**
     * Delete the tailing blank space and print the terminating character,* as well as a new line 
     */
    printf("\b%c\n",tc);

    return 0; /* Return 0 upon successful program execution */
}

输出

http://drp.ly/1nYt5J

解决方法

另一种思考方法
you can cage a swallow can't you?
uoy t'nac wollaws a egac nac uoy?
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
you t'nac wollaws a egac nac uoy?
^^^
you can't wollaws a egac nac uoy?
    ^^^^^
you can't swallow a egac nac uoy?
          ^^^^^^^
you can't swallow a egac nac uoy?
                  ^
you can't swallow a cage nac uoy?
                    ^^^^
you can't swallow a cage can uoy?
                         ^^^
you can't swallow a cage can you?
                             ^^^

对于你要反转的每件事(无论是整句还是单词):

>找到开始和结束
>交换开头和结尾字符
>一次“向内”移动
>坚持到达“中间”

由于反转字符串的块是一种常见的操作,因此将其作为自己的函数是有意义的.由于该功能需要完成其工作的唯一信息是:

>字符串
>开始索引
>结束指数

您认为该功能的参数是什么?

需要反复做的另一件常见的事情是“找到”某些东西,无论是空格还是标点符号.您可能需要自己编写,或者如果您可以使用库函数,或者想要提示,请查找:

man strcspn

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