我正在尝试在C中为我的
shell实现多个管道.
我只有一个管道功能管道| b但不是| b | C.
int c[2]; int returnv; pid_t id; pipe(c); pid = fork()) == 0 if (pid) { dup2(c[1],0); close(p[1]); close(p[1]); execvp(array(0),array); } if ((pid = fork()) == 0) { dup2(p[0],1); close(p(0)); close(p[0]); returnv = execvp(array[0],array); } close(p[1]); wait(NULL); wait(NULL); wait(NULL); return returnv;
这是第二个版本:
int i = 0; while (i < x) { pipe(c); if ((pid = fork()) == 0) { dup2(t[i],1); if (i < 2) dup2(p[0],1); close(p[1]); r= execvp(cmd[i][0],cmd[i]); } wait(NULL); close(p[0]); i += 1; t[i] = p[1];
解决方法
编辑:根据您的评论
要执行多重管道,您需要将所有命令存储在某处.
这就是我使用结构选项卡的原因.
检查这个新版本可能更容易理解
首先,您需要一个选项卡或其他东西来存储所有命令:
int main() { char *ls[] = {"ls",NULL}; char *grep[] = {"grep","pipe",NULL}; char *wc[] = {"wc",NULL}; char **cmd[] = {ls,grep,wc,NULL}; loop_pipe(cmd); return (0); }
void loop_pipe(char ***cmd) { int p[2]; pid_t pid; int fd_in = 0; while (*cmd != NULL) { pipe(p); if ((pid = fork()) == -1) { exit(EXIT_FAILURE); } else if (pid == 0) { dup2(fd_in,0); //change the input according to the old one if (*(cmd + 1) != NULL) dup2(p[1],1); close(p[0]); execvp((*cmd)[0],*cmd); exit(EXIT_FAILURE); } else { wait(NULL); close(p[1]); fd_in = p[0]; //save the input for the next command cmd++; } } }