struct B1{
int d;
void fb(){};
};
struct B2 : B1{
using B1::d;
using B1::fb;
int d; // why this gives error?
void fb(){} // and this does not?
};
int main(){}
是因为,B1 :: fb()被视为B1 :: fb(B1 *)和B2 :: fb()被视为B2 :: fb(B2 *)？也就是说,隐含参数,有助于区分这些吗？
$13.3.1/4-
For nonconversion functions introduced
by a using-declaration into a derived
class,the function is considered to
be a member of the derived class for
the purpose of defining the type of
the implicit object parameter.
解决方法
When a using-declaration brings names from a base class into a derived class scope,member functions in the derived class override and/or hide member functions with the same name and parameter types in a base class (rather than conflicting).
在您的示例中,B2 :: fb()隐藏了using声明引入的B1 :: fb().
至于为什么两者都使用B1 :: d是不正确的;和int d;在B2的定义中,C标准(C03§7.3.3/ 10)解释了：
Since a using-declaration is a declaration,the restrictions on declarations of the same name in the same declarative region also apply to using-declarations.
因此,由于以下形式不正确,它的结构不正确：它会在单个声明区域中生成两个具有相同名称的对象：
struct S { int d; int d; };
