我有以下代码段：
char* filename;
unsigned long long int bytesToTransfer;
int fd,pagesize;
char *data;
fd = open(filename,O_RDONLY);
if (fd==NULL){
fputs ("File error",stderr);
exit (1);
}
cout << "File Open: " << filename << endl;
pagesize = getpagesize();
data = mmap((caddr_t)0,bytesToTransfer,PROT_READ,MAP_SHARED,fd,0);
if (*data == -1) {
fputs ("Memory error",stderr);
exit (2);
}
cout << "Data to Send: " << data << endl;
但是当我编译时,我会收到：
error: invalid conversion from ‘void*’ to ‘char*’ [-fpermissive]
data = mmap((caddr_t)0,0);
有人能给我一个暗示什么是错的吗？
解决方法
C不执行void *的隐式强制转换,你必须明确这一点
data = static_cast<char*>(mmap((caddr_t)0,0));
