#include <iostream>
#include <tree>
using namespace std;
int main()
{
tree<int> myTree;
tree<int>::iterator i = myTree.root();
*i = 42;
tree<int>::iterator j = i.add_child();
*j = 777;
j = j.parent();
if (i == myTree.root() && i == j) cout << "i and j are both pointing to the root\n";
return 0;
}
谢谢你,tree.hh似乎正是我想要的.
If this is for gaining the benefit of
a data-structure holding arbitrary
index types,optimized for searching
and good at insertion then consider
using a map.A map is an associative container that
has performance guarantees identical
to those of a tree: logarithmic
searching,logarithmic insertion,
logarithmic deletion,linear space.
Internally they are often implemented
as red-black trees,although that is
not a guarantee. Still,as an STL user
all you should care about is the
performance guarantees of the STL
algorithms and data-structures.
Whether they’re implemented as trees
or little green men shouldn’t matter
to you.
我不确定地图是否是我需要的,但感谢您的信息.我会记得尽可能使用地图而不是实现树.
解决方法
不同.
int main(int,char **)
{
tree<string> tr;
tree<string>::iterator top,one,two,loc,banana;
top=tr.begin();
one=tr.insert(top,"one");
two=tr.append_child(one,"two");
tr.append_child(two,"apple");
banana=tr.append_child(two,"banana");
tr.append_child(banana,"cherry");
tr.append_child(two,"peach");
tr.append_child(one,"three");
loc=find(tr.begin(),tr.end(),"two");
if(loc!=tr.end()) {
tree<string>::sibling_iterator sib=tr.begin(loc);
while(sib!=tr.end(loc)) {
cout << (*sib) << endl;
++sib;
}
cout << endl;
tree<string>::iterator sib2=tr.begin(loc);
tree<string>::iterator end2=tr.end(loc);
while(sib2!=end2) {
for(int i=0; i<tr.depth(sib2)-2; ++i)
cout << " ";
cout << (*sib2) << endl;
++sib2;
}
}
}
现在有什么不同？在实施时,您的实施更简单
将节点附加到树.
虽然你的版本简单易懂,但是这个lib的开发者可能想要在不浏览树的情况下访问一些信息,例如树的大小.
我还假设他不希望出于性能原因将根存储在所有节点上.因此,如果你想按照自己的方式实现它,我建议你保留大部分逻辑并将链接添加到迭代器中的父树,并重写一点.
