在shell脚本中从被调用的函数返回值

我想从shell脚本中调用的函数返回值。也许我缺少语法。我试着使用全局变量。但这也不行。代码是：

lockdir="somedir"
test() {
    retval=""

    if mkdir "$lockdir"
        then    # directory did not exist,but was created successfully
            echo >&2 "successfully acquired lock: $lockdir"
            retval="true"
        else
            echo >&2 "cannot acquire lock,giving up on $lockdir"
            retval="false"
    fi
    return retval
}


retval=test()
if [ "$retval" == "true" ]
    then
        echo "directory not created"
    else
        echo "directory already created"
fi

bash函数不能直接返回一个字符串，就像你想要的。你可以做三件事：

> echo一个字符串
>返回退出状态，这是一个数字，而不是字符串
>共享变量

这对于一些其他壳也是正确的。

以下是执行每个选项的方法：

回声字符串

lockdir="somedir"
testlock(){
    retval=""
    if mkdir "$lockdir"
    then # directory did not exist,but was created successfully
         echo >&2 "successfully acquired lock: $lockdir"
         retval="true"
    else
         echo >&2 "cannot acquire lock,giving up on $lockdir"
         retval="false"
    fi
    echo "$retval"
}

retval=$( testlock )
if [ "$retval" == "true" ]
then
     echo "directory not created"
else
     echo "directory already created"
fi

2.返回退出状态

lockdir="somedir"
testlock(){
    if mkdir "$lockdir"
    then # directory did not exist,but was created successfully
         echo >&2 "successfully acquired lock: $lockdir"
         retval=0
    else
         echo >&2 "cannot acquire lock,giving up on $lockdir"
         retval=1
    fi
    return "$retval"
}

testlock
retval=$?
if [ "$retval" == 0 ]
then
     echo "directory not created"
else
     echo "directory already created"
fi

共享变量

lockdir="somedir"
retval=-1
testlock(){
    if mkdir "$lockdir"
    then # directory did not exist,giving up on $lockdir"
         retval=1
    fi
}

testlock
if [ "$retval" == 0 ]
then
     echo "directory not created"
else
     echo "directory already created"
fi

原文链接：https://www.f2er.com/bash/391522.html

在shell脚本中从被调用的函数返回值

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