array=(a b c d)
我想在数组的每个元素之前添加一个字符为了有这个
array=(^a ^b ^c ^d)
一个简单的方法是循环使用数组元素并逐个更改值
for i in "${#array[@]}"
do
array[i]="^"array[i]
done
但我想知道是否有任何方式做同样的事情没有循环数组，因为我必须做所有的元素相同的指令。
提前致谢。
array=("${array[@]/#/^}")
从文档：
${parameter/pattern/string}
Pattern substitution. The pattern is expanded to produce a pattern just as in pathname expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. If pattern begins with /,all matches of pattern are replaced with string. Normally only the first match is replaced. If pattern begins with #,it must match at the beginning of the expanded value of parameter. If pattern begins with %,it must match at the end of the expanded value of parameter. If string is null,matches of pattern are deleted and the / following pattern may be omitted. If parameter is @ or *,the substitution operation is applied to each positional parameter in turn,and the expansion is the resultant list. If parameter is an array variable subscripted with @ or *,the substitution operation is applied to each member of the array in turn,and the expansion is the resultant list.
