Bash脚本,在while循环中有多个条件

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我试图得到一个简单的while循环工作在bash使用两个条件,但尝试了许多不同的语法从各种论坛,我不能停止抛出一个错误。这里是我有:
while [ $stats -gt 300 ] -o [ $stats -eq 0 ]

我也试过:

while [[ $stats -gt 300 ] || [ $stats -eq 0 ]]

…以及其他几个结构。我想要这个循环继续,而$ stats是> 300或$ stats = 0。

正确的选项是(按推荐顺序):
# Single POSIX test command with -o operator (not recommended anymore).
# Quotes strongly recommended to guard against empty or undefined variables.
while [ "$stats" -gt 300 -o "$stats" -eq 0 ]

# Two POSIX test commands joined in a list with ||.
# Quotes strongly recommended to guard against empty or undefined variables.
while [ "$stats" -gt 300 ] || [ "$stats" -eq 0 ]

# Two bash conditional expressions joined in a list with ||.
while [[ $stats -gt 300 ]] || [[ $stats -eq 0 ]]

# A single bash conditional expression with the || operator.
while [[ $stats -gt 300 || $stats -eq 0 ]]

# Two bash arithmetic expressions joined in a list with ||.
# $ optional,as a string can only be interpreted as a variable
while (( stats > 300 )) || (( stats == 0 ))

# And finally,a single bash arithmetic expression with the || operator.
# $ optional,as a string can only be interpreted as a variable
while (( stats > 300 || stats == 0 ))

一些注意事项:

>引用[[…]]和((…)中的参数扩展是可选的;如果未设置变量,-gt和-eq将假定值为0。>使用$是可选内部((…)),但使用它可以帮助避免无意的错误。如果没有设置stats,那么((stats> 300))将假定stats == 0,但是(($ stats> 300))将产生语法错误

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