参见英文答案 >
Simple logical operators in Bash3答案我不知道如何做一个如果在shell中多个测试，我有麻烦写这个脚本：
echo "You have provided the following arguments $arg1 $arg2 $arg3"
if [ "$arg1" = "$arg2" && "$arg1" != "$arg3" ]
then
echo "Two of the provided args are equal."
exit 3
elif [ $arg1 = $arg2 && $arg1 = $arg3 ]
then
echo "All of the specified args are equal"
exit 0
else
echo "All of the specified args are different"
exit 4
fi
问题是我每次得到这个错误：./compare.sh：[：missing`]’command not found
谢谢！
sh解释&&作为shell运算符。将其更改为-a，这是[的连接运算符：
原文链接：https://www.f2er.com/bash/388892.html[ "$arg1" = "$arg2" -a "$arg1" != "$arg3" ]
此外，你应该总是引用变量，因为[当你离开参数时感到困惑。
