我试图将参数作为for循环的最大限制传递，如下所示：
#!/bin/bash
for i in {1..$1}
do
echo $i
done
这样当用参数2调用时返回{1..2}，而不是执行脚本并给我
1 2
大括号内不做变量替换。您可以使用固定数字而不是变量。
原文链接：https://www.f2er.com/bash/387324.htmlBrace Expansion
A sequence expression takes the form {x..y},where x and y are either integers or single characters. …
Brace expansion is performed before any other expansions,and any characters special to other expansions are preserved in the result. It is strictly textual. Bash does not apply any syntactic interpretation to the context of the expansion or the text between the braces.
A correctly-formed brace expansion must contain unquoted opening and closing braces,and at least one unquoted comma or a valid sequence expression. Any incorrectly formed brace expansion is left unchanged.
尝试以下其中一种：
for ((i = 1; i <= $1; i++)); do
echo $i
done
# Not recommended with large sequences.
for i in $(seq 1 $1); do
echo $i
done
