我需要在倒数计时器循环中收听任何按键.如果按下任何键,倒计时器应该突破它的循环.这主要是有效的,除了输入键只是让倒数计时器更快.
#!/bin/bash
for (( i=30; i>0; i--)); do
printf "\rStarting script in $i seconds. Hit any key to continue."
read -s -n 1 -t 1 key
if [[ $key ]]
then
break
fi
done
echo "Resume script"
我似乎无法找到任何在线任何位置检测输入密钥的示例.
我认为基于读取的返回代码,可以解决这个问题.从阅读的手册页,
原文链接：https://www.f2er.com/bash/387085.htmlThe return code is zero,unless end-of-file is encountered,read times out,or an invalid file descriptor is supplied as the argument to -u.
超时的返回码似乎是142 [在Fedora 16中验证]
所以,脚本可以修改为,
#!/bin/bash
for (( i=30; i>0; i--)); do
printf "\rStarting script in $i seconds. Hit any key to continue."
read -s -n 1 -t 1 key
if [ $? -eq 0 ]
then
break
fi
done
echo "Resume script"
