我写了一个bash脚本,它应该从文件中读取用户名和IP地址,并通过ssh对它们执行命令.
这是hosts.txt：
user1 192.168.56.232 user2 192.168.56.233
这是myScript.sh：
cmd="ls -l" while read line do set $line echo "HOST:" $1@$2 ssh $1@$2 $cmd exitStatus=$? echo "Exit Status: " $exitStatus done < hosts.txt
问题是执行似乎在第一个主机完成后停止.这是输出：
$./myScript.sh HOST: user1@192.168.56.232 total 2748 drwxr-xr-x 2 user1 user1 4096 2011-11-15 20:01 Desktop drwxr-xr-x 2 user1 user1 4096 2011-11-10 20:37 Documents ... drwxr-xr-x 2 user1 user1 4096 2011-11-10 20:37 Videos Exit Status: 0 $
为什么会这样,我该如何解决？
在您的脚本中,ssh作业获取与读取行相同的标准输入,并且在您的情况下恰好在第一次调用时占用所有行.因此读取线只能看到
输入的第一行.
原文链接：https://www.f2er.com/bash/387075.html输入的第一行.
解决方案：关闭sdin的stdin,或者从/ dev / null更好地重定向. (有些计划
不喜欢stdin关闭)
while read line
do
ssh server somecommand </dev/null # Redirect stdin from /dev/null
# for ssh command
# (Does not affect the other commands)
printf '%s\n' "$line"
done < hosts.txt
如果您不想为/ dev / null重定向循环中的每个作业,您还可以尝试以下方法之一：
while read line
do
{
commands...
} </dev/null # Redirect stdin from /dev/null for all
# commands inside the braces
done < hosts.txt
# In the following,let's not override the original stdin. Open hosts.txt on fd3
# instead
while read line <&3 # execute read command with fd0 (stdin) backed up from fd3
do
commands... # inside,you still have the original stdin
# (maybe the terminal) from outside,which can be practical.
done 3< hosts.txt # make hosts.txt available as fd3 for all commands in the
# loop (so fd0 (stdin) will be unaffected)
# totally safe way: close fd3 for all inner commands at once
while read line <&3
do
{
commands...
} 3<&-
done 3< hosts.txt
