我需要帮助将输出(stdin和stdout)从系统命令发送到bash函数,同时仍然接受参数的输入.像下面的例子.有人可以指出我正确的道路吗？
LogMsg()
{
DateTime=`date "+%Y/%m/%d %H:%M:%S"`
echo '*****'$DateTime' ('$QMAKESPEC'): '$1 >> "$LogFile"
echo $DateTime' ('$QMAKESPEC'): '$1
}
# Already works
LogMsg "This statement is sent directly"
# Wish I could do this:
# Capture both stdout & stderr of a system function to the logfile
# I do not presume that any of the Syntax that follows is good
make 2>&1 >(LogMsg)
为此,您可以使用
read bash内置：
LogMsg()
{
read IN # This reads a string from stdin and stores it in a variable called IN
DateTime=`date "+%Y/%m/%d %H:%M:%S"`
echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
echo $DateTime' ('$QMAKESPEC'): '$IN
}
然后使用管道：
make 2>&1 | LogMsg
更新：
为了能够使用stdin或一个参数作为输入(根据chepner的评论),您可以这样做：
LogMsg()
{
if [ -n "$1" ]
then
IN="$1"
else
read IN # This reads a string from stdin and stores it in a variable called IN
fi
DateTime=`date "+%Y/%m/%d %H:%M:%S"`
echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
echo $DateTime' ('$QMAKESPEC'): '$IN
}
