我希望〜/ .bashrc在改变其内容时将成为源码.我用这样的东西创建了一个bashrc类：
file { "/root/.bashrc":
ensure => present,owner => root,group => root,mode => 0644,source => "puppet:///bashrc/root/.bashrc"
}
exec { "root_bashrc":
command => "source /root/.bashrc",subscribe => File["/root/.bashrc"],}
但是如你所知,source是一个shell内置命令,运行代理时出现以下错误：
# puppet agent --no-daemonize --verbose notice: Starting Puppet client version 2.7.1 info: Caching catalog for svr051-4170 info: Applying configuration version '1311563901' err: /Stage[main]/Bashrc/Exec[root_bashrc]/returns: change from notrun to 0 Failed: Could not find command 'source' notice: Finished catalog run in 2.28 seconds notice: Caught INT; calling stop
有没有办法解决这个问题？
在Puppet中重新获取新的.bashrc是没有意义的,因为它将在子shell中运行,并且更改不会传播到您当前的shell(我认为,这是您尝试做的事情).你不能做你想做的事(我想).
原文链接：https://www.f2er.com/bash/385631.html