我进入了每个PHP项目(大约25个！),一些sh脚本帮助我完成日常任务,如部署,repo同步,数据库导出/导出等.
对于我管理的所有项目,sh脚本都是相同的,因此必须有一个配置文件来存储依赖于项目的不同参数：
# example conf,the sintaxys only needs to be able to have comments and be easy to edit. host=www.host.com administrator_email=guill@company.com password=xxx
我只需要找到一种干净的方法,可以从sh脚本中读取(解析)此配置文件,同时,能够从我的PHP脚本中读取这些相同的参数.无需使用XML.
你知道一个很好的解决方案吗？
吉列尔莫
如果您不想像pavanlimo所示那样获取文件,另一个选择是使用循环来引入变量：
原文链接：https://www.f2er.com/bash/385476.htmlwhile read propline ; do # ignore comment lines echo "$propline" | grep "^#" >/dev/null 2>&1 && continue # if not empty,set the property using declare [ ! -z "$propline" ] && declare $propline done < /path/to/config/file
在PHP中,相同的基本概念适用：
// it's been a long time,but this is probably close to what you need
function isDeclaration($line) {
return $line[0] != '#' && strpos($line,"=");
}
$filename = "/path/to/config/file";
$handle = fopen($filename,"r");
$contents = fread($handle,filesize($filename));
$lines = explode("\n",$contents); // assuming unix style
// since we're only interested in declarations,filter accordingly.
$decls = array_filter($lines,"isDeclaration");
// Now you can iterator over $decls exploding on "=" to see param/value
fclose($handle);
