在
shell脚本(在.zshrc中)我试图执行一个命令,该命令作为字符串存储在另一个变量中.网络上的各种消息来源说这是可能的,但我没有得到我期望的行为.也许这是命令开头的〜,或者也许是使用sudo,我不确定.有任何想法吗？谢谢
function update_install()
{
# builds up a command as a string...
local install_cmd="$(make_install_command $@)"
# At this point the command as a string looks like: "sudo ~some_server/bin/do_install arg1 arg2"
print "----------------------------------------------------------------------------"
print "Will update install"
print "With command: ${install_cmd}"
print "----------------------------------------------------------------------------"
echo "trying backticks"
`${install_cmd}`
echo "Trying \$()"
$(${install_cmd})
echo "Trying \$="
$=install_cmd
}
输出：
Will update install With command: sudo ~some_server/bin/do_install arg1 arg2 trying backticks update_install:9: no such file or directory: sudo ~some_server/bin/do_install arg1 arg2 Trying $() update_install:11: no such file or directory: sudo ~some_server/bin/do_install arg1 arg2 Trying $= sudo ~some_server/bin/do_install arg1 arg2: command not found
使用eval：
原文链接：https://www.f2er.com/bash/385174.htmleval ${install_cmd}
