bash – 在文件中第一次出现特定字符串之前删除所有行

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基本上我有一个像这样的文件
junk
morejunk
somestring
bats
car
somestring
bats
car
somestring
bats
car

我想在第一次出现somestring之前删除所有垃圾,以便文件看起来像

somestring
bats
car
somestring
bats
car
somestring
bats
car

我按照this question的建议使用sed -i’0,/ somestring /,d’file.txt,但是当我想将该行保留为第一行时,它会删除第一次出现somestring的行.

使用sed你可以使用:
sed -i '/somestring/,$!d' file

替换表达式的说明:

, matches lines starting from where the first
address matches,and continues until the second match
(inclusively).

$ matches the last line of the last file of input,
or the last line of each file when the -i or -s options are
specified.

! If the character follows an address range,then only lines
which do not match the address range will be selected.

d Delete the pattern space; immediately start next cycle.

结果:

$sed -i '/somestring/,$!d' file
somestring
bats
car
somestring
bats
car
somestring
bats
car
原文链接:https://www.f2er.com/bash/384995.html

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