我正在尝试创建一个脚本,循环使用以下格式编写文件名的文件：yyyymmdd.hh.filename.
脚本被调用：
./loopscript.sh 20091026.00 23 ./loopscript.sh 20091026.11 15 ./loopscript.sh 20091026.09 20091027.17
需要脚本来检查这两个给定日期/小时之间的每小时.
例如
cat 20091026.00.filename |more cat 20091026.01.filename |more ... cat 20091026.23.filename |more cat 20091027.01.filename |more cat 20091027.02.filename |more ...
等等.
有什么想法呢？标准的0 – x循环没有任何困难.或简单的循环.只是不知道如何去上述.
要在两个给定的日期/时间之间处理每个文件,您可以使用以下内容：
#!/usr/bin/bash
#set -x
usage() {
echo 'Usage: loopscript.sh <from> <to>'
echo ' <from> MUST be yyyymmdd.hh or empty,meaning 00000000.00'
echo ' <to> can be shorter and is affected by <from>'
echo ' e.g.,20091026.00 27.01 becomes'
echo ' 20091026.00 20091027.01'
echo ' If empty,it is set to 99999999.99'
echo 'Arguments were:'
echo " '${from}'"
echo " '${to}'"
}
# Check parameters.
from="00000000.00"
to="99999999.99"
if [[ ! -z "$1" ]] ; then
from=$1
fi
if [[ ! -z "$2" ]] ; then
to=$2
fi
## Insert this to default to rest-of-day when first argument
## but no second argument. Basically just sets second
## argument to 23 so it will be transformed to end-of-day.
#if [[ ! -z "$1"]] ; then
# if [[ -z "$2"]] ; then
# to=23
# fi
#fi
if [[ ${#from} -ne 11 || ${#to} -gt 11 ]] ; then
usage
exit 1
fi
# Sneaky code to modify a short "to" based on the start of "from".
# ${#from} is the length of ${from}.
# $((${#from}-${#to})) is the length difference between ${from} and ${to}
# ${from:0:$((${#from}-${#to}))} is the start of ${from} long enough
# to make ${to} the same length.
# ${from:0:$((${#from}-${#to}))}${to} is that with ${to} appended.
# Voila! Easy,no?
if [[ ${#to} -lt ${#from} ]] ; then
to=${from:0:$((${#from}-${#to}))}${to}
fi
# Process all files,checking that they're inside the range.
echo "From ${from} to ${to}"
for file in [0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9].[0-9][0-9].* ; do
if [[ ! ( ${file:0:11} < ${from} || ${file:0:11} > ${to} ) ]] ; then
echo " ${file}"
fi
done
当您创建文件20091026.00.${RANDOM}到20091028.23.${RANDOM}包含,这是几个示例运行：
pax> ./loopscript.sh 20091026.07 9 From 20091026.07 to 20091026.09 20091026.07.21772 20091026.08.31390 20091026.09.9214 pax> ./loopscript.sh 20091027.21 28.02 From 20091027.21 to 20091028.02 20091027.21.22582 20091027.22.30063 20091027.23.29437 20091028.00.14744 20091028.01.6827 20091028.02.10366 pax> ./loopscript.sh 00000000.00 99999999.99 # or just leave off the parameters. 20091026.00.25772 20091026.01.25964 20091026.02.21132 20091026.03.3116 20091026.04.6271 20091026.05.14870 20091026.06.28826 : : : 20091028.17.20089 20091028.18.13816 20091028.19.7650 20091028.20.20927 20091028.21.13248 20091028.22.9125 20091028.23.7870
你可以看到,第一个参数必须是正确的格式yyyymmdd.hh.第二个参数可以缩短,因为它继承了第一个参数的开始以使其成为正确的长度.
这只会尝试处理存在的文件(从ls)和正确的格式,而不是每个范围内的每个日期/时间.如果您有稀疏文件(包括在范围的开始和结束),这将更有效,因为它不需要检查文件是否存在.
顺便说一下,这是创建测试文件的命令,如果你有兴趣：
pax> for dt in 20091026 20091027 20091028 ; do
for tm in 00 01 02 ... you get the idea ... 21 22 23 ; do
touch $dt.$tm.$RANDOM
done
done
请不要逐字输入,然后抱怨它创建的文件如下：
20091026.you.12345 20091028.idea.77
我只修剪了一行,所以它符合代码宽度. 原文链接：https://www.f2er.com/bash/383921.html
