我想写一个打印命令的bash脚本.但出于可读性目的,我不希望它打印echo命令.不幸的是,我找不到正确的bash脚本设置来实现这一点.我需要帮助？
#!/bin/bash # Makes the bash script to print out every command before it is executed set -v echo "Cleaning test database" RAILS_ENV=test bundle exec rake db:drop echo "************************************************************" echo "" echo "Setting up the test database" RAILS_ENV=test bundle exec rake db:setup echo "************************************************************" echo ""
输出如下：
echo "Cleaning test database" Cleaning test database RAILS_ENV=test bundle exec rake db:drop echo "************************************************************" ************************************************************ echo "" echo "Setting up the test database" Setting up the test database RAILS_ENV=test bundle exec rake db:setup
如您所见,它打印出所有命令,包括echo命令,我不想看到它.
你有什么想法？
干杯,
赫拉尔
您可以使用trap DEBUG而不是set -v作为一个选项.
原文链接：https://www.f2er.com/bash/383376.html例如
#!/bin/bash # Makes the bash script to print out every command before it is executed except echo trap '[[ $BASH_COMMAND != echo* ]] && echo $BASH_COMMAND' DEBUG echo "Cleaning test database" RAILS_ENV=test bundle exec rake db:drop echo "************************************************************" echo "" echo "Setting up the test database" RAILS_ENV=test bundle exec rake db:setup echo "************************************************************" echo ""
每次命令后都会执行调试.
$BASH_COMMAND目前正在运行命令.
BASH_COMMAND
The command currently being executed or about to be executed,unless the shell is executing a command as the result of a trap,in which case it is the command executing at the time of the trap.
所以陷阱只是检查最后一个命令是否没有以echo开头并打印出来.
