你能告诉我如何迭代列表中的项目可以包含空格吗？
x=("some word","other word","third word")
for word in $x ; do
echo -e "$word\n"
done
如何强制输出：
some word other word third word
代替：
some word (...) third word
要正确循环项目,您需要使用${var [@]}.并且您需要引用它以确保带有空格的项目不会被拆分：“${var [@]}”.
原文链接：https://www.f2er.com/bash/383302.html全部一起：
x=("some word" "other word" "third word")
for word in "${x[@]}" ; do
echo -e "$word\n"
done
或者,saner(thanks Charles Duffy)与printf：
x=("some word" "other word" "third word")
for word in "${x[@]}" ; do
printf '%s\n\n' "$word"
done
