我正在学习ASP.NET MVC 3并尝试使用单个表单创建一个View,该表单由通过外键链接在一起的多个模型组成.最终目标是将单个表单插入到所有数据库表中.
问题是我无法弄清楚为什么当我右键单击创建视图时,表单不会在cshtml文件中自动生成.自动生成的代码有很多帮助,因为我有许多链接在一起的表,以及我必须验证和插入的许多字段.如果无法自动生成表单,那么最有效/优雅的方法是什么？
这是我所拥有的简化.
模型：
class Customer
{
[Key]
public UInt64 CustomerId { get; set; }
[required(ErrorMessage = "Name is required.")]
[Display(Name = "Customer Name")]
[MaxLength(50)]
public string FullName { get; set; }
}
class CustomerAdditionalDetails1
{
[ForeignKey("Customer")]
public UInt64 CustomerId { get; set; }
[required(ErrorMessage = "This info is required.")]
[Display(Name = "Customer Information")]
[MaxLength(50)]
public string SomeInfo { get; set; }
}
class CustomerAdditionalDetails2
{ // same foreign key as CustomerAddtionalDetails1,but with different properties
}
class CustomerAdditionalDetails3
{ // same foreign key as CustomerAddtionalDetails1,but with different properties
}
...
public class CustomerModel
{
public Customer Customer { get; set; }
public CustomerAdditionalDetails1 CustomerAdditionalDetails1 { get; set; }
public CustomerAdditionalDetails2 CustomerAdditionalDetails2 { get; set; }
public CustomerAdditionalDetails3 CustomerAdditionalDetails3 { get; set; }
...
}
控制器：
public ActionResult Submit()
{
return View();
}
[HttpPost]
public ActionResult Submit(CustomerModel customer)
{
return View();
}
请帮忙！
解决方法
生成视图时,是否基于CustomerModel创建强类型视图？如果您正在生成视图,则不会在页面中输出任何值,因为所有属性都是对其他对象的引用.您需要脚手架模型中包含的实际值类型,以自动将它们包含在视图中.也就是说,您可以按照下面的示例自行将它们添加到视图中.
另外我在你的控制器中注意到你的GET方法没有将模型返回给要渲染的视图.如果要根据模型生成视图,则需要传递要为其生成的对象.
@model MvcApplication3.Models.CustomerModel
@{
ViewBag.Title = "Index";
}
<h2>Index</h2>
<fieldset>
<legend>CustomerModel</legend>
</fieldset>
<ul>
<li>@Model.Customer.FullName</li>
<li>@Model.CustomerAdditionalDetails1.SomeInfo1</li>
<li>@Model.CustomerAdditionalDetails2.SomeInfo2</li>
</ul>
<p>
@Html.ActionLink("Edit","Edit",new { /* id=Model.PrimaryKey */ }) |
@Html.ActionLink("Back to List","Index")
</p>
public class CustomerController : Controller
{
public ActionResult Index()
{
CustomerModel customerModel = new CustomerModel()
{
Customer = new Customer()
{
FullName = "Dan"
},CustomerAdditionalDetails1 = new CustomerAdditionalDetails1()
{
SomeInfo1 = "Somewhere1"
},CustomerAdditionalDetails2 = new CustomerAdditionalDetails2()
{
SomeInfo2 = "Somewhere2"
},CustomerAdditionalDetails3 = new CustomerAdditionalDetails3()
{
SomeInfo3 = "Somewhere3"
}
};
return View(customerModel);
}
}
