我在ASP.NET MVC site
in a way like suggests this post中实现了错误处理.
404错误都可以正常工作.但是如何正确显示用户友好的屏幕401错误？他们通常不会抛出可以在Application_Error()中处理的异常,而是返回HttpUnauthorizedResult.一种可能的方法是将以下代码添加到Application_EndRequest()方法的末尾
if (Context.Response.StatusCode == 401)
{
throw new HttpException(401,"You are not authorised");
// or UserFriendlyErrorRedirect(new HttpException(401,"You are not authorised")),witout exception
}
但在Application_EndRequest()Context.Session == null,errorController.Execute()失败,因为它不能使用默认的TempDataProvider.
// Call target Controller and pass the routeData.
IController errorController = new ErrorController();
errorController.Execute(new RequestContext(
new HttpContextWrapper(Context),routeData)); // Additional information: The SessionStateTempDataProvider requires SessionState to be enabled.
那么你能建议一些最佳实践,如何在ASP.NET MVC应用程序中“用户友好的处理”401？
谢谢.
解决方法
看看HandleErrorAttribute.从它的子类或添加您自己的实现,将处理您感兴趣的所有状态代码.您可以使它为每个错误类型返回单独的错误视图.
这是一个如何创建你的句柄错误异常过滤器的想法.我抛出了大部分的东西,只关注我们的要领.绝对看一下原来的实现,添加参数检查和其他重要的事情.
public class HandleManyErrorsAttribute : FilterAttribute,IExceptionFilter
{
public virtual void OnException(ExceptionContext filterContext)
{
if (filterContext.ExceptionHandled || !filterContext.HttpContext.IsCustomErrorEnabled)
return;
Exception exception = filterContext.Exception;
string viewName = string.Empty;
object viewmodel = null;
int httpCode = new HttpException(null,exception).GetHttpCode();
if (httpCode == 500)
{
viewName = "Error500View";
viewmodel = new Error500Model();
}
else if (httpCode == 404)
{
viewName = "Error404View";
viewmodel = new Error404Model();
}
else if (httpCode == 401)
{
viewName = "Error401View";
viewmodel = new Error401Model();
}
string controllerName = (string)filterContext.RouteData.Values["controller"];
string actionName = (string)filterContext.RouteData.Values["action"];
filterContext.Result = new ViewResult
{
ViewName = viewName,MasterName = Master,ViewData = viewmodel,TempData = filterContext.Controller.TempData
};
filterContext.ExceptionHandled = true;
filterContext.HttpContext.Response.Clear();
filterContext.HttpContext.Response.StatusCode = httpCode;
filterContext.HttpContext.Response.TrySkipIisCustomErrors = true;
}
}
然后,使用此属性“装饰”控制器操作：
[HandleManyErrors]
public ActionResult DoSomethingBuggy ()
{
// ...
}
