我已经创建了一个新的干净的asp.net 5项目(rc1-final).使用身份认证我只需要ApplicationDbContext.cs与以下代码：
public class ApplicationDbContext : IdentityDbContext<ApplicationUser>
{
protected override void OnModelCreating(ModelBuilder builder)
{
// On event model creating
base.OnModelCreating(builder);
}
}
请注意ApplicationDbContext使用IdentityDbContext而不是DbContext.
有任何IdentityConfig.cs.我需要把经典的保护覆盖void Seed来创建角色和用户,如果它不存在？
解决方法
我这样做的方法是在模型命名空间中创建一个类.
public class SampleData
{
public static void Initialize(IServiceProvider serviceProvider)
{
var context = serviceProvider.GetService<ApplicationDbContext>();
string[] roles = new string[] { "Owner","Administrator","Manager","Editor","Buyer","Business","Seller","Subscriber" };
foreach (string role in roles)
{
var roleStore = new RoleStore<IdentityRole>(context);
if (!context.Roles.Any(r => r.Name == role))
{
roleStore.CreateAsync(new IdentityRole(role));
}
}
var user = new ApplicationUser
{
FirstName = "Muhammad",LastName = "Abdullah",Email = "abdullahnaseer999@gmail.com",NormalizedEmail = "ABDULLAHNASEER999@GMAIL.COM",UserName = "Owner",NormalizedUserName = "OWNER",PhoneNumber = "+923366633352",EmailConfirmed = true,PhoneNumberConfirmed = true,SecurityStamp = Guid.NewGuid().ToString("D")
};
if (!context.Users.Any(u => u.UserName == user.UserName))
{
var password = new PasswordHasher<ApplicationUser>();
var hashed = password.HashPassword(user,"secret");
user.PasswordHash = hashed;
var userStore = new UserStore<ApplicationUser>(context);
var result = userStore.CreateAsync(user);
}
AssignRoles(serviceProvider,user.Email,roles);
context.SaveChangesAsync();
}
public static async Task<IdentityResult> AssignRoles(IServiceProvider services,string email,string[] roles)
{
UserManager<ApplicationUser> _userManager = services.GetService<UserManager<ApplicationUser>>();
ApplicationUser user = await _userManager.FindByEmailAsync(email);
var result = await _userManager.AddToRolesAsync(user,roles);
return result;
}
}
在启动时运行此代码.在Startup.cs的配置方法结束后,路由配置后添加以下代码作为Stafford Williams说.
SampleData.Initialize(app.ApplicationServices);
