<li ng-repeat="item in (filteredItems = (items | filter:query))">
  {{ item.name }}
</a>

在控制器中,我想根据他的一个属性获取项目的索引.

精度：我想在过滤列表中获取索引,而不是在整个列表中.

例如,这将是项目名称为some_item_7的索引.

var app = angular.module('myApp',[]);

app.controller('MyCtrl',['$scope',function MyCtrl($scope) {

    $scope.query = 'some';

    $scope.items = 
    [
      { name: 'some_item_1' },{ name: 'another_item_2' },{ name: 'some_item_3' },{ name: 'another_item_4' },{ name: 'some_item_5' },{ name: 'another_item_6' },{ name: 'some_item_7' },{ name: 'another_item_8' },{ name: 'some_item_9' }
    ];

    $scope.itemNext = function (item) {
      console.log(item.name);
    };

    $scope.getIndexFromName = function (name) {
      console.log("trying to get the index of the item with name = " + name);
    }

    $scope.getIndexFromName('some_item_7');

  }
]);

http://plnkr.co/edit/C8gL9qV1MyonTwDENO9L?p=preview

任何的想法 ？