在AngularJS Typescript中从父类创建子实例

如何从父方法为子类创建实例？

例如：

class Vehicle {
    public getNewInstance(): ICar {
        // What should be here? 
        return new XXXXXXXX; 
    }
}
 
class Car extends Vehicle {
    public getWheels(): Number {
        return 4;
    }
}

现在,我需要这样做以获得一个新的Car实例：

Car.getNewInstance();

车辆有许多扩展类,我防止在每个孩子中重复代码.此外,儿童班也有更多的孩子.

解决方法

您的代码不会这样做,因为您需要静态方法而不是实例方法.

你可以这样做：

class Vehicle {
    public static getNewInstance(): Vehicle {
        return new this();
    }
 
    public getWheels(): Number {
        throw new Error("unknown number of wheels for abstract Vehicle");
    }
}
 
class Car extends Vehicle {
    public getWheels(): Number {
        return 4;
    }
}

因为Vehicle现在有一个静态getNewInstance方法,所以所有扩展类也都有.
所以：

let v = Vehicle.getNewInstance();
console.log(v); // Vehicle {}
console.log(v.getWheels()); // Uncaught Error: unknown number of wheels for abstract Vehicle
 
let c = Car.getNewInstance();
console.log(c); // Car {}
console.log(c.getWheels()); // 4

编辑

如果我误解了你并且你确实想在现有实例上调用getNewInstance,那么你可以这样做：

abstract class Vehicle {
    public abstract getNewInstance(): Vehicle;
}
 
class Car extends Vehicle {
    public getNewInstance(): Vehicle {
        return new Car();
    }
 
    public getWheels(): Number {
        return 4;
    }
}

或这个：

class Vehicle {
    private ctor: { new (): Vehicle };
 
    constructor(ctor: { new (): Vehicle }) {
        this.ctor = ctor;
    }
 
    public getNewInstance(): Vehicle {
        return new this.ctor();
    }
}
 
class Car extends Vehicle {
    constructor() {
        super(Car);
    }
 
    public getWheels(): Number {
        return 4;
    }
}

在AngularJS Typescript中从父类创建子实例

解决方法

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