我习惯使用角度为1的$q.我正在迁移到角度2.
是否有提供.when()方法的等价物?
例如,我需要迁移这个:
.service('updateProDB',[ '$rootScope','connectionStatus','$q','storageService','sendToServer','$ionicPopup',function ($rootScope,connectionStatus,$q,storageService,sendToServer,$ionicPopup) { 'use strict'; var dbReadyDeferred = $q.defer(),prodata = [],prodataFieldNames = []; this.get = function () { var debugOptionUseLocalDB = 0,serverAttempts = 0; if (debugOptionUseLocalDB) { return fallbackToLocalDBfileOrLocalStorageDB(); } if (connectionStatus.f() === 'online') { console.log("Fetching DB from the server:"); return getDBfileXHR(dbUrl(),serverAttempts) .then(function () { // success console.log('-normal XHR request succeeded.'); return dbReadyDeferred.promise; }) .catch(function (){
解决方法
你可以做同等的,用:
Promise.resolve(promise).then
这基本上不区分承诺和价值观.
是的,你可以用同样的方式实例化q,但使用新的Promise()而不是$q()
let promise = Promise((resolve,reject) => { if (/* some async task */) { resolve('Success!'); } else { reject('Oops... something went wrong'); } });
和
let promise = $q((resolve,reject) => { if (/* some async task */) { resolve('Success!'); } else { reject('Oops... something went wrong'); } });
应该是等价的