我使用Angular 2(TypeScript)。
我想做一些新的选择，但我得到的onChange()总是最后的选择。如何获得新的选择？
<select [(ng-model)]="selectedDevice" (change)="onChange($event)">
<option *ng-for="#i of devices">{{i}}</option>
</select>
onChange($event) {
console.log(this.selectedDevice);
// I want to do something here for new selectedDevice,but what I
// got here is always last selection,not the one I just select.
}
如果你不需要双向数据绑定：
原文链接：https://www.f2er.com/angularjs/146912.html<select (change)="onChange($event.target.value)">
<option *ngFor="let i of devices">{{i}}</option>
</select>
onChange(deviceValue) {
console.log(deviceValue);
}
对于双向数据绑定，分离事件和属性绑定：
<select [ngModel]="selectedDevice" (ngModelChange)="onChange($event)" name="sel2">
<option [value]="i" *ngFor="let i of devices">{{i}}</option>
</select>
export class AppComponent {
devices = 'one two three'.split(' ');
selectedDevice = 'two';
onChange(newValue) {
console.log(newValue);
this.selectedDevice = newValue;
// ... do other stuff here ...
}
如果设备是对象数组，请绑定到ngValue而不是值：
<select [ngModel]="selectedDeviceObj" (ngModelChange)="onChangeObj($event)" name="sel3">
<option [ngValue]="i" *ngFor="let i of deviceObjects">{{i.name}}</option>
</select>
{{selectedDeviceObj | json}}
export class AppComponent {
deviceObjects = [{name: 1},{name: 2},{name: 3}];
selectedDeviceObj = this.deviceObjects[1];
onChangeObj(newObj) {
console.log(newObj);
this.selectedDeviceObj = newObj;
// ... do other stuff here ...
}
}
