$scope.property = new Property();
$scope.property.propertyType = {};
$scope.propertyTypes = [
{ value: 'ResidentialPlot',name: 'Residential Plot' },{ value: 'CommercialPlot',name: 'Commercial Plot' },{ value: 'Apartment',name: 'Apartment/Flat' },{ value: 'Townhouse',name: 'Townhouse' },{ value: 'House',name: 'Single Family House' },{ value: 'Commercial',name: 'Commercial Property' }
];
<label for="ptype" class="col-sm-2 control-label">Property Type</label>
<p>Populated: {{property.propertyType}}</p>
<ui-select ng-model="property.propertyType" id="ptype" theme="selectize" ng-disabled="disabled" style="width: 300px;" title="Choose Property Type">
<ui-select-match placeholder="Select a Property Type">{{$select.selected.value}}</ui-select-match>
<ui-select-choices repeat="propType in propertyTypes">
<span ng-bind-html="propType.name"></span>
<small ng-bind-html="propType.value"></small>
</ui-select-choices>
这给了我
$scope.PropertyType = {"value":"Apartment","name":"Apartment/Flat"}
我的模式中的PropertyType只是一个字符串,所以我想绑定所选的值而不是选定的JSON项.
$scope.PropertyType = "Apartment"
我应该绑定到我的ng模型来得到这个？
您需要将选择输入中的ng-model属性更改为selected_propertyType,并在更改时观察它,然后提取值并将其分配给propertyType
$scope.property = new Property();
$scope.property.propertyType = {};
$scope.propertyTypes = [
{ value: 'ResidentialPlot',name: 'Commercial Property' }
];
$scope.$watch('selected_propertyType',function(newValue,oldValue){
if (newValue && newValue!=oldValue){
$scope.propertyType = $scope.selected_propertyType.value;
}
})
<label for="ptype" class="col-sm-2 control-label">Property Type</label>
<p>Populated: {{property.selected_propertyType}}</p>
<ui-select ng-model="property.selected_propertyType" id="ptype" theme="selectize" ng-disabled="disabled" style="width: 300px;" title="Choose Property Type">
<ui-select-match placeholder="Select a Property Type">{{$select.selected.value}}</ui-select-match>
<ui-select-choices repeat="propType in propertyTypes">
<span ng-bind-html="propType.name"></span>
<small ng-bind-html="propType.value"></small>
</ui-select-choices>
