基本上我有一个运行整个项目的Main类.代码工作正常但是一旦App没有聚焦它变得不活跃.我想知道如何将它作为一项服务.一个会在启动时启动.

该应用程序将是用于通知的单向消息系统. I.E.

桌面客户端 – > Openfire Server – > Android XMPP服务 – >存储(DB) – >用于显示的Android GUI

正如我所说,代码正在运行(连接,登录,接收),但不是服务.

我可以使用BEEM源,但它太功能和隔行扫描.我是一个轻量级的服务.

代码：

public class MainActivity extends Activity {

  public static final String HOST = "fire.example.com";
  public static final int PORT = 5222;
  public static final String SERVICE = "example.com";
  public static final String USERNAME = "metest@fire.example.com";
  public static final String PASSWORD = "mepass";

  private XMPPConnection connection;
  private ArrayListFailed to connect to "+ connection.getHost());
             Log.e("XMPPChatActivity",ex.toString());
             setConnection(null);
         }
          try {
            connection.login(USERNAME,PASSWORD);
            Log.i("XMPPChatActivity","Logged in as" + connection.getUser());

            // Set the status to available
            Presence presence = new Presence(Presence.Type.available);
            connection.sendPacket(presence);
            setConnection(connection);

            Roster roster = connection.getRoster();
            CollectionFailed to log in as "+  USERNAME);
                Log.e("XMPPChatActivity",ex.toString());
                setConnection(null);
              }
              dialog.dismiss();
           }
      });
    t.start();
    dialog.show();
  }
}

所以基本上,我如何使这项服务