我在twitter上工作,我有访问令牌,我现在也收到推文我想在推特上回复,就像我们在Twitter网站上做的那样我使用下面的代码,但它不是回复推文但它更新我的状态请帮我解决这个问题谢谢..
public void tweetReply() {
try {
// System.out.println("Post Id= " + itemsObj.postId);
AccessToken a = new AccessToken(twittertokens[0],twittertokens[1]);
Twitter twitter = new TwitterFactory().getInstance();
twitter = new TwitterFactory().getInstance();
twitter.setOAuthConsumer(Constants.CONSUMER_KEY,Constants.CONSUMER_SECRET);
twitter.setOAuthAccessToken(a);
Long id = new Long("236178766597087234");
twitter.updateStatus(new StatusUpdate("@lalitrajput024 this is to test For reply option ").inReplyToStatusId(id));
} catch (Exception e) {
// TODO: handle exception
}
}
解决方法
我也遇到了这个问题,然后我尝试在文本中使用处理程序.现在它似乎正在工作.
public static void reply(long inReplyToStatusId,String text,double latitude,double longitude,TwitterFactory factory) throws TwitterException
{ AccessToken accessToken = loadAccessToken();
Twitter twitter = factory.getInstance();
twitter.setOAuthConsumer(consumerKey,consumerSecrate);
twitter.setOAuthAccessToken(accessToken);
StatusUpdate stat= new StatusUpdate(text);
stat.setInReplyToStatusId(inReplyToStatusId);
GeoLocation location= new GeoLocation(latitude,longitude);
stat.setLocation(location);
twitter.updateStatus(stat);
}'
我称之为
reply(238912922250792960l,"@praveena_kd testing reply",12.787,77.7578,factory);
