我编写了一个代码来从联系人中获取联系人姓名,电话号码和图像,并将其显示在
android的listview中.它工作正常,但需要更多时间来加载.我曾尝试在代码的某些部分使用多线程.但加载时间并未减少.
这是onCreate()方法:
protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); lvDetail = (ListView) findViewById(R.id.listView1); fetchcontacts(); lvDetail.setAdapter(new MyBaseAdapter(context,myList)); }
private void fetchcontacts() { // TODO Auto-generated method stub Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null,ContactsContract.Contacts.DISPLAY_NAME + " ASC"); int count = cursor.getCount(); if (count > 0) { Toast.makeText(context,"count >0",Toast.LENGTH_SHORT).show(); while (cursor.moveToNext()) { String columnId = ContactsContract.Contacts._ID; int cursorIndex = cursor.getColumnIndex(columnId); String id = cursor.getString(cursorIndex); name = cursor.getString(cursor .getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)); Toast.makeText(context,"Toast 1",Toast.LENGTH_SHORT).show(); int numCount = Integer.parseInt(cursor.getString(cursor .getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))); if (numCount > 0) { Toast.makeText(context,"Toast 2",Toast.LENGTH_SHORT).show(); Cursor phoneCursor = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI,CommonDataKinds.Phone.CONTACT_ID+" = ?",new String[] { id },ContactsContract.Contacts.DISPLAY_NAME + " ASC"); while (phoneCursor.moveToNext()) { Toast.makeText(context,"Toast 3",Toast.LENGTH_SHORT).show(); phoneNo = phoneCursor.getString(phoneCursor .getColumnIndex(ContactsContract.CommonDataKinds. Phone.NUMBER)); String image_uri = phoneCursor .getString(phoneCursor .getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI)); if (image_uri != null) { Toast.makeText(context,"Toast 4",Toast.LENGTH_SHORT).show(); System.out.println(Uri.parse(image_uri)); try { bitmap = MediaStore.Images.Media .getBitmap(this.getContentResolver(),Uri.parse(image_uri)); // sb.append("\n Image in Bitmap:" + bitmap); // System.out.println(bitmap); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } Toast.makeText(context,name,Toast.LENGTH_SHORT).show(); getDataInList(name,phoneNo,bitmap); name=null; phoneNo=null; Drawable myDrawable = getResources().getDrawable(R.drawable.star1); bitmap = ((BitmapDrawable) myDrawable).getBitmap(); } phoneCursor.close(); } } }
这里,listview的setAdapter()函数在将所有联系人提取到ArrayList之后正在工作.有没有人知道如何在获取联系人期间显示联系人?任何示例代码?
解决方法@H_404_14@
1.从光标中读取您只需要的列,根据您的要求,您只需要_ID,HAS_PHONE_NUMBER,DISPLAY_NAME,所以更改光标读数
Cursor cursor = getContentResolver().query(
ContactsContract.Contacts.CONTENT_URI,new String[] { ContactsContract.Contacts._ID,ContactsContract.Contacts.HAS_PHONE_NUMBER,ContactsContract.Contacts.DISPLAY_NAME },ContactsContract.Contacts.DISPLAY_NAME + " ASC");
2.不要在UI线程中执行时间过程.请使用AsyncTask
注意:这两个步骤将在某种程度上解决.但不完全
Cursor cursor = getContentResolver().query( ContactsContract.Contacts.CONTENT_URI,new String[] { ContactsContract.Contacts._ID,ContactsContract.Contacts.HAS_PHONE_NUMBER,ContactsContract.Contacts.DISPLAY_NAME },ContactsContract.Contacts.DISPLAY_NAME + " ASC");
2.不要在UI线程中执行时间过程.请使用AsyncTask
注意:这两个步骤将在某种程度上解决.但不完全