我编写了一个代码来从联系人中获取联系人姓名,电话号码和图像,并将其显示在
android的listview中.它工作正常,但需要更多时间来加载.我曾尝试在代码的某些部分使用多线程.但加载时间并未减少.
这是onCreate()方法：
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lvDetail = (ListView) findViewById(R.id.listView1);
fetchcontacts();
lvDetail.setAdapter(new MyBaseAdapter(context,myList));
}
private void fetchcontacts() {
// TODO Auto-generated method stub
Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null,ContactsContract.Contacts.DISPLAY_NAME + " ASC");
int count = cursor.getCount();
if (count > 0) {
Toast.makeText(context,"count >0",Toast.LENGTH_SHORT).show();
while (cursor.moveToNext()) {
String columnId = ContactsContract.Contacts._ID;
int cursorIndex = cursor.getColumnIndex(columnId);
String id = cursor.getString(cursorIndex);
name = cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
Toast.makeText(context,"Toast 1",Toast.LENGTH_SHORT).show();
int numCount = Integer.parseInt(cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)));
if (numCount > 0) {
Toast.makeText(context,"Toast 2",Toast.LENGTH_SHORT).show();
Cursor phoneCursor = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,CommonDataKinds.Phone.CONTACT_ID+" = ?",new String[] { id
},ContactsContract.Contacts.DISPLAY_NAME + " ASC");
while (phoneCursor.moveToNext()) {
Toast.makeText(context,"Toast 3",Toast.LENGTH_SHORT).show();
phoneNo = phoneCursor.getString(phoneCursor
.getColumnIndex(ContactsContract.CommonDataKinds.
Phone.NUMBER));
String image_uri = phoneCursor
.getString(phoneCursor
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI));
if (image_uri != null) {
Toast.makeText(context,"Toast 4",Toast.LENGTH_SHORT).show();
System.out.println(Uri.parse(image_uri));
try {
bitmap = MediaStore.Images.Media
.getBitmap(this.getContentResolver(),Uri.parse(image_uri));
// sb.append("\n Image in Bitmap:" + bitmap);
// System.out.println(bitmap);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Toast.makeText(context,name,Toast.LENGTH_SHORT).show();
getDataInList(name,phoneNo,bitmap);
name=null;
phoneNo=null;
Drawable myDrawable = getResources().getDrawable(R.drawable.star1);
bitmap = ((BitmapDrawable) myDrawable).getBitmap();
}
phoneCursor.close();
}
}
}
这里,listview的setAdapter()函数在将所有联系人提取到ArrayList之后正在工作.有没有人知道如何在获取联系人期间显示联系人？任何示例代码？
解决方法
1.从光标中读取您只需要的列,根据您的要求,您只需要_ID,HAS_PHONE_NUMBER,DISPLAY_NAME,所以更改光标读数
Cursor cursor = getContentResolver().query(
ContactsContract.Contacts.CONTENT_URI,new String[] { ContactsContract.Contacts._ID,ContactsContract.Contacts.HAS_PHONE_NUMBER,ContactsContract.Contacts.DISPLAY_NAME },ContactsContract.Contacts.DISPLAY_NAME + " ASC");
2.不要在UI线程中执行时间过程.请使用AsyncTask
注意：这两个步骤将在某种程度上解决.但不完全
