我使用以下代码:
@H_502_2@public class Settings extends Activity implements OnClickListener {
private Activity activity;
private AlertDialog.Builder builder;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
this.requestWindowFeature(Window.FEATURE_NO_TITLE);
setContentView(R.layout.settings);
Button bAdd = (Button) findViewById(R.id.bAdd);
bAdd.setOnClickListener(this);
activity = this;
builder = new AlertDialog.Builder(activity);
builder.setMessage("message")
.setTitle("title");
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
switch (v.getId()) {
case R.id.bAdd:
AlertDialog dialog = builder.create();
break;
}
}
}
但由于某种原因,我的弹出窗口没有出现,什么也没做.有什么想法导致这种故障?谢谢!
解决方法
您必须调用show()方法而不是create().
注意:create()方法只创建Dialog的实例,但不会显示它.
一个建议:
您可以创建返回Dialog的方法,如下所示:
@H_502_2@public Dialog createNewDialog(int type) { AlertDialog dlg = null; switch (type) { case SOME_CONSTANT: dlg = new AlertDialog.Builder(ActivityName.this / this) .setTitle("Title") .setMessage("Message") .setPositiveButton("Yes",null) .create(); break; } }然后你可以称之为:
@H_502_2@createNewDialog(SOME_CONSTANT).show();并显示您的对话框.
特别是在您的情况下,您可以使用以下代码片段达到目标:
@H_502_2@@Override public void onClick(View v) { // TODO Auto-generated method stub switch (v.getId()) { case R.id.bAdd: createNewDialog(SOME_CONSTANT).show(); break; } }希望能帮助到你.